Matematika Sekolah Menengah Atas jawab sekarang pliss

jawab sekarang pliss

بِسْـــمِ اللَّهِ الرَّحْمَــنِ الرَّحِيْمِ

Nomor 1:

f(x) = x³ + 3x² - x + 5

f(12) = 2³ + 3(2)² - 2 + 5

= 8 + 3 × 4 - 2 + 5

= 8 + 12 - 2 + 5

= 20 - 2 + 5

= 23

Nomor 2:

f(x) = x³ + x² - 4

g(x) = x³ - 2x² + x + 2

  • f(x) + g(x)

f(x) + g(x) = (x³ + x² - 4) + (x³ - 2x² + x + 2)

f(x) + g(x) = x³ + x² - 4 + x³ - 2x² + x + 2

f(x) + g(x) = 2x³ - x² + x - 2

  • f(x) - g(x)

f(x) - g(x) = (x³ + x² - 4) - (x³ - 2x² + x + 2)

f(x) - g(x) = x³ + x² - 4 - x³ + 2x² - x - 2

f(x) - g(x) = 3x² - x - 6

  • f(x) g(x)

f(x) • g(x) = (x³ + x² - 4) • (x³ - 2x² + x + 2)

f(x) • g(x) = x^6 - 6x^5 + x^4 + 2x^3 + x^5 - 2x^4 + x^3 + 2x^2 - 4x^3 - 8x^2 - 4x - 8

f(x) • g(x) = x^6 - 5x^5 - x^4 - x^3 - 6x^2 - 4x - 8

Nomor 3:

| 1 2 3 -5

2 | 2 8 22

|____________ +

1 4 11 17

Hasil bagi = x² + 4x + 11

Sisa = 17

Nomor 4:

x² + 4x + 11 ----> Hasil bagi

______________

x - 2 / x³ + 2x² + 3x - 5

/ x³ - 2x²

______________ –

4x² + 3x - 5

4x² - 8x

___________ –

11x - 5

11x - 22

_______ –

17 ----> Sisa

وَاللَّهُ عَالَمُ بِاالصَّوَافَ

-S-

Penjelasan dengan langkah-langkah:

1).

f(2) = 2³ + 3(2)² - 2 + 5

= 8 + 12 - 2 + 5 = 23

2).

f(x) = x³ + x² - 4

g(x) = x³ - 2x² + x + 2

a). f(x) + g(x)

(x³ + x² - 4) + (x³ - 2x² + x + 2) =

x³ + x³ + x² - 2x² + x - 4 + 2 =

2x³ + x² + x - 2

b). f(x) - g(x)

(x³ + x² - 4) - (x³ - 2x² + x + 2) =

x³ - x³ + x² + 2x² - x - 4 - 2 =

3x² - x - 6

c). f(x).g(x)

(x³ + x² - 4) . (x³ - 2x² + x + 2) =

(x³. x³) + (x³. (-2x²)) + (x³. x) + (x³. 2) + (x².x³) + (x².(-2x²)) + (x². x) + (x². 2) + ((-4). x³) + ((-4).(-2x²)) + ((-4). x) + ((-4).2) =

x^6 - 2x^5 + x⁴ + 2x³ + x^5 - 2x⁴ + x³ + 2x² - 4x³ + 8x² - 4x - 8 =

x^6 - x^5 - x⁴ - x³ + 10x² - 8

3. harus digambar

4. harus digambar

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